49x^2-35x=-4

Solution for 49x^2-35x=-4 equation:

49x^2-35x=-4

We move all terms to the left:

49x^2-35x-(-4)=0

We add all the numbers together, and all the variables

49x^2-35x+4=0

a = 49; b = -35; c = +4;
Δ = b2-4ac
Δ = -352-4·49·4
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-21}{2*49}=\frac{14}{98}
=1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+21}{2*49}=\frac{56}{98}
=4/7
$